Sunday, February 20, 2011

Full Time Roulette

With this “Full Time Roulette Strategy” you have acquired a perfect remedy for adverse for adverse runs on the roulette table. Finally it is possible to play without tabulating and observation for previous results to base your next bet on. No more lengthy waiting and no more bookkeeping, and still having the assurance of winning all the time, with or without favourable runs for the player; moreover the wild swings of results and the dry spells (the laws of average completely) are successfully held in check

  • One dollar on number one. Number 22 comes up. A Loss.
  • One dollar each on number 1 and 2, or two dollars on the split line between numbers 1 and 2. Number 15 comes up. A Loss.
  • One dollar each on number 1, 2, and 3, or three dollars stacked on the bottom of number 1 to 3. Number 34 comes up. A Loss.
  • One dollar each on number 1, 2, 3, and 4, or three dollars stacked on the bottom of number 1 to 3, plus one dollar straight up on number 4. Number 9 comes up. A Loss.
  • One dollar each on number 1, 2, 3, 4, 5, or three dollars stacked on the bottom of number 1, 2, 3, and two dollars on the split of numbers 4 and 5. plus one dollar straight up on number 4. Zero comes up. A Loss.
  • One dollar each on number 1, 2, 3, 4, 5, 6, or six dollars stacked on the bottom of number 1 to 6, covering all six numbers on the street position. 22 comes up. A Loss.
So far we have risked and lost 21 dollars.

  • Twelve dollars stacked on the bottom of the first six numbers 1 to 6 and two dollars on number 7 straight up. 4 comes up. A WIN.
  • Twelve dollars in a stack to cover 1 to 6, four dollars on the split between 7 and 8 (or two dollars each on the 7 and 8 straight up). Number 34 comes up. A Loss.
  • Twelve dollars in a stack to cover 1 to 6, two dollars each on 7, 8, and 9, (or six dollars in a stack to cover number 7, 8, and 9). Number 5 comes up. A WIN.
  • Twelve dollars stacked covering 1 to 6, six dollars covering 7-9, two dollars each on the 10 and the 11 straight up. (or four dollars on the split between 10 and 11).Number 17 comes up. A Loss.
  • Twelve dollars stacked covering 1 to 6, plus twelve dollars stacked to cover numbers 7-12 (or twenty-four dollars on the first dozen on the outside).Number 5 comes up again. A WIN.
  • Thirty-six dollars on the first dozen on the outside, covering the first twelve numbers and three dollars straight up on the number 13. Number 33 comes up. A Loss.
  • Thirty-six dollars on the first dozen on the outside, six dollars on the split between 13 and 14 (or three dollars each straight up on the number 13, 14, and 15). Number 23 comes up. A Loss.
  • Thirty-six dollars on the first dozen on the outside, nine dollars stacked to cover 13, 14, 15, three dollars straight up on number 16. Number 3 comes up. A WIN.
  • Thirty-six dollars on the first dozen on the outside, nine dollars stacked for 13, 14,15, three dollars each straight up on number 16 and 17 (or six dollars on the split between 16 and 17). Number 19 comes up. A Loss.
  • Thirty-six dollars on the first dozen on the outside, nine dollars stacked for 13, 14,15, and nine dollars stacked for 16, 17, 18 (or much simpler 54 dollars on the outside betting space for number 1 to 18). Number 11 comes up. A WIN.

Total profit stands at 126 dollars.

Here is a quick graphic illustration of the whole system. We do nothing else but always cover one more number with each successive bet, up to, if necessary number 18. one dollar for the first six bets, two dollars for the next six bets, and three dollars for the last six bets.

We start with one dollar betting number 1. Then we bet one dollar each on number 1 and 2. Then one dollar each on 1, 2, and 3. then we cover numbers 1, 2, 3, 4, with one dollar each. Then we add number 5, next we add number 6.

In diagram from our betting scheme looks like this:

Bankroll needed to go all the way is $414 in you play with one dollar chips. If you are playing at a $5 minimum table, cover the first five numbers on your first bet,then six numbers, seven numbers, etc.If you show a profit you don’t have to bet all 18 numbers. Break off the sequence and start over and play until you show a acceptable profit again. You can always start from scratch again with the small bets and repeat the profitable performance. You can also use the strategy on the high numbers 19 to 36.

3 comments:

  1. Can you help me do the math on this American roulette bet, assuming a $5 min table:

    On the inside,
    bet 3 $dollars on the 10-13 line (same as a $1 dollar split on 10-13, plus $1 dollar split on 11-14 plus $1 split on 12-15) pays $17
    $3 dollars on the 22-25 line pays $17
    $1 dollar on the 0-00 split pays $17

    On the outside,
    $7 dollars on the 2nd third pays $14

    so, $14 dollars risked on each roll


    I figure this covers 20 out of the 38 spots,
    any one of those spots hitting pays at least $14 (six spots: 16 thru 21),
    some pay $17 (eight spots: 0,00, 10,11,12,25,26,27)
    and some pay "both ways" inside and outside bet $14+$17 = $31 (6 spots: 13,14,15,22,23,24)
    I lose $14 on 18 spots: 1 thru 9 and 28 thru 36


    Over time, shouldn't I come out with a slight edge?

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  3. Hi. So if you win at last with 18 numbers covered and a total consumption of 414 units, you win 35*3units=105units. How is that a profitable strategy?

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